Skip to content

fix: Rename misleading stderr variable to stdout in print_output macro #1222

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
atosneo wants to merge 1 commit into
base: main
Choose a base branch
from
Open

fix: Rename misleading stderr variable to stdout in print_output macro #1222

Changes from all commits
Commits
Show all changes
1 commit
Select commit
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
4 changes: 2 additions & 2 deletions src/main.rs
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -92,11 +92,11 @@ macro_rules! print_output {
($($arg:tt)*) => {
use std::io::Write;

let stderr = std::io::stdout();
let stdout = std::io::stdout();


{
let mut handle = stderr.lock();
let mut handle = stdout.lock();
// We can write on stdout, so we simply ignore the error and don't print
// and stop with success.
let res = handle.write_all(std::format!($($arg)*).as_bytes());
Expand Down